Ay nako 1st time ko nagalit sa klase ko. Ang ingay ingay kasi. Sino ba naman bang gaganahan magturo nun? Bukod pa dun, yung mga boys hindi pa gumagawa ng SW. Ano feeling nila ha? Pinaderive ko kasi yung equation ng adiabatic process ng thermodynamics. Last week tinuro ko lahat ng basics ng Algebra na gagamitin sa equation. Lahat ng earlier lessons ko was made to ready them dun sa derivation ng formula na yun. Bonus pa nga nilagay ko pa sa left side nung board yung mga properties ng Algebra na gagamitin nila. Aba ang mga boys walang tinag nakatungaga! Eto ang script ko sa kanila:

”Nakakainis na kayo ah! Ang ingay ingay nyo! Hindi kayo gumagawa ng seatwork! Anong akala nyo ha?! Ako ang magdedecide kung makakapag-USTET kayo o hinde! Ako ang Director ng TP4 kayo ako ang may say! Hindi kayo matutulungan ng CSC dahil ako ang kakausap sa OSA! Kung ganyan din naman pala ang ugali nyo, you don’t deserve to be a Thomasian! Dun nyo sa PLM ikalat yang kabastusan nyo sa teacher!”


In all my teaching experience sa TP4, un pa lang talaga ang first time na nagalit ako. I can say that I’m a really cool teacher, and many will be willing to testify for it. Ewan ko bas a batch nay un. Pero I’m sure to trim them down. Mabibigay ako ng surprise exam that will stip them of their happiness! Ha! Akala nila ah!

Well anyway gutso ko yung lessons namin sa Algebra, kasi Word Problems na kami. Dun ko na malalaman kung sino talaga yung nag-iisip. Nag-bigay din kasi ako ng mental exercise sa kanila. Wala din nakasagot. Ang tanong kasi. The congruent sides of a isosceles triangle is 10 cm, the third side is 12 cm. What is the measure of the side of the largest square that is inscribed within the triangle?

Ang sabi naman kasi nila eh nakapag-geometry naman sila. So alam ko alam nila yung mga postulates and properties regarding the triangle. Ewan ko din kung baket hindi nila nasagot yung tanong. Ganito lang nman kasimple yun.

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The object is to be drawn just like the one above. The side of the square inside the triangle is unknown and is represented as x. If I bisect the base, it will result to having two right triangles. Using part of the triangle, we can solve for the height of the triangle using the Pythagorean Theorem. 102 = h2 + 62. Observe that the x that is parallel to the base. It’s now coincides with both the congruent sides. Using the property of triangles we can conclude that they are similar triangles.

Reason: The three angles of both triangles are congruent.
Proof:
1) The angle at the top is congruent to itself by the reflexive postulate.
2) They are right triangles therefore they both have 90 degree angles.
3) The angles beside the 90 degree angles of both triangles are congruent by using the property of parallel lines. Alternate interior angles are congruent.

Because they are similar triangles, we can apply ratio and proportion.
Base of big triangle/height of big triangle = base of small triangle/height of small triangle

6 / 8 = 8-x / x/2

Solve for x:

x = 2.9 ~ 3 cm

Sisiw diba? Ewan ko ba! Hindi kasi namin finilter yun eh. Si Kuya Ney kasi sabi nya tanggapin na lahat. Well, ififilter ko sila bago magexam. Tignan lang naten.